NextMockપરીક્ષાઓ શોધો, દા.ત. SSC CGL, UPPSC, Lekhpal
State PCS PYQPrelims 2025

BPSC – Combined Competitive Examination · પ્રશ્ન 121

We apply a force of 200 newtons on a wooden box and push it across the floor at constant velocity. The friction force will be:

  1. 100 N
  2. 200 N
  3. 300 N
  4. 400 N
જવાબ બતાવો અને સમજૂતી

જવાબ: (B) 200 N

સમજૂતી

By Newton's first law, zero acceleration means the forces balance: friction = 200 N.

  • (A) ખોટો

    Wrong: at constant velocity net force is zero, so friction equals 200 N.

  • (B) સાચો

    Correct: constant velocity means applied force = friction = 200 N.

  • (C) ખોટો

    Wrong: friction cannot exceed the applied force if velocity is constant.

  • (D) ખોટો

    Wrong: not balanced with 200 N.