3x = 4y = 12-z ಆದರೆ, \(\frac{3}{x} + \frac{3}{y} + \frac{3}{z}\) ರ ಮೌಲ್ಯವನ್ನು ಕಂಡುಹಿಡಿಯಿರಿ. A. 1 B. 6 C. 4 D. 0

Let 3^x = 4^y = 12^(−z) = k. Then 3 = k^(1/x), 4 = k^(1/y) and 12 = k^(−1/z). Since 3 × 4 = 12, 1/x + 1/y = −1/z, so 1/x + 1/y + 1/z = 0 and the expression is 0.