12, 15, 18 आणि 27 ने भागल्यास अनुक्रमे 10, 13, 16 आणि 25 बाकी उरेल अशी लहानात लहान संख्या शोधा.

In each case the remainder is 2 less than the divisor (12 − 10 = 15 − 13 = 18 − 16 = 27 − 25 = 2). So the number is 2 less than a common multiple. LCM(12, 15, 18, 27) = 540, so the least number = 540 − 2 = 538.