RRB NTPC · प्रश्न 54
जर Cot \(x = \frac{5}{12}\) आहे, तर Sec x + Cosec x = ?
उत्तर दाखवा आणि स्पष्टीकरण
उत्तर: (B) 221/60
स्पष्टीकरण
cot x = 5/12 gives a 5–12–13 triangle: sec x = 13/5 and cosec x = 13/12. Sum = 156/60 + 65/60 = 221/60.
RRB NTPC · प्रश्न 54
उत्तर: (B) 221/60
cot x = 5/12 gives a 5–12–13 triangle: sec x = 13/5 and cosec x = 13/12. Sum = 156/60 + 65/60 = 221/60.