यदि p^2 + q^2 - r^2 = 0 है, तो (p6 + q6 - r6) ÷ p2q2r2 का मान कितना होगा?

Let a = p², b = q², c = −r². Then a + b + c = 0, so a³ + b³ + c³ = 3abc, i.e. p⁶ + q⁶ − r⁶ = −3p²q²r². Dividing by p²q²r² gives −3.