2(sin^6θ + cos^6θ) - 3(sin^4θ + cos^4θ) बराबर है:

sin⁶θ + cos⁶θ = 1 − 3sin²θcos²θ and sin⁴θ + cos⁴θ = 1 − 2sin²θcos²θ. So the expression = 2 − 6s²c² − 3 + 6s²c² = −1.