Railways PYQCBT 2 2017

RRB NTPC · प्रश्न 54

यदि Cot \(x = \frac{5}{12}\) है, तो Sec x + Cosec x = ?

  1. 216/60

  2. 221/60

  3. 313/156

  4. 209/60

उत्तर देखें और व्याख्या

उत्तर: (B) 221/60

व्याख्या

cot x = 5/12 gives a 5–12–13 triangle: sec x = 13/5 and cosec x = 13/12. Sum = 156/60 + 65/60 = 221/60.