RRB NTPC · प्रश्न 54
यदि Cot \(x = \frac{5}{12}\) है, तो Sec x + Cosec x = ?
उत्तर देखें और व्याख्या
उत्तर: (B) 221/60
व्याख्या
cot x = 5/12 gives a 5–12–13 triangle: sec x = 13/5 and cosec x = 13/12. Sum = 156/60 + 65/60 = 221/60.
RRB NTPC · प्रश्न 54
उत्तर: (B) 221/60
cot x = 5/12 gives a 5–12–13 triangle: sec x = 13/5 and cosec x = 13/12. Sum = 156/60 + 65/60 = 221/60.