RRB NTPC · प्रश्न 91
यदि \(\cos \theta = \dfrac{4}{5}, \sec \theta + \tan \theta = ?\)
उत्तर देखें और व्याख्या
उत्तर: (A) 2
व्याख्या
cos θ = 4/5 gives a 3–4–5 triangle: sec θ = 5/4 and tan θ = 3/4. Sum = 8/4 = 2.
RRB NTPC · प्रश्न 91
उत्तर: (A) 2
cos θ = 4/5 gives a 3–4–5 triangle: sec θ = 5/4 and tan θ = 3/4. Sum = 8/4 = 2.