RRB NTPC · प्रश्न 21
जर \(\sin A = \dfrac{4}{5}\) आणि \(\sin B = \dfrac{5}{13}\) , तर Sin (A + B) = ? A. \(\dfrac{63}{65}\) B. \(\dfrac{16}{65}\) C. \(\dfrac{33}{65}\) D. \(\dfrac{56}{65}\)
उत्तर दाखवा आणि स्पष्टीकरण
उत्तर: (A) A
स्पष्टीकरण
sin A = 4/5 gives cos A = 3/5; sin B = 5/13 gives cos B = 12/13. sin(A + B) = sin A cos B + cos A sin B = 48/65 + 15/65 = 63/65.