जर \(\frac{1}{\sin^265^\circ+\cos^265^\circ}+\frac{\sin15^\circ}{\cos75^\circ}+\frac{\cos65^\circ}{\sin25^\circ}=\sqrt{3}tanθ\) असेल, तर θ चे मूल्य काढा:

45°
60°
90°
30°

उत्तर दाखवा आणि स्पष्टीकरण

उत्तर: (B) 60°

स्पष्टीकरण

sin²65° + cos²65° = 1, so the first term is 1. sin 15° = cos 75° and cos 65° = sin 25°, so the other terms are 1 each. Total = 3 = √3 tan θ, so tan θ = √3 and θ = 60°.