RRB NTPC · Question 13
If \(\cot x = \dfrac{5}{12}\), then sin x - sec x =? A. \(-\dfrac{229}{65}\) B. \(\dfrac{229}{65}\) C. \(\dfrac{109}{65}\) D. \(-\dfrac{109}{65}\)
Show answer & explanation
Answer: (B) D
Explanation
cot x = 5/12 gives a 5–12–13 triangle: sin x = 12/13 and cos x = 5/13, so sec x = 13/5. sin x − sec x = 12/13 − 13/5 = (60 − 169)/65 = −109/65.