RRB NTPC · Question 87
A tube has two punctures. First puncture empties the tank in 29 mins and second puncture empties the tank in 6 minutes. If the leakage is at certain rate, then find the time taken by both punctures to empty the tank. A. \(\dfrac{34}{35}\) B. \(3 \dfrac{34}{35}\) C. \(4\dfrac{33}{35}\) D. \(4\dfrac{34}{35}\)
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Answer: (A) D
Explanation
Together the punctures empty 1/29 + 1/6 = 35/174 of the tube per minute, so they take 174/35 = 4 34/35 minutes.