RRB NTPC · Question 52
If \(sin\;x = \frac{4}{5}\) then sec^2 x – 1 = ? A. \(\frac{{16}}{{25}}\) B. \(\frac{{25}}{{9}}\) C.\(\frac{{9}}{{16}}\) D. \(\frac{{16}}{{9}}\)
Show answer & explanation
Answer: (B) D
Explanation
sec²x − 1 = tan²x. sin x = 4/5 gives cos x = 3/5, so tan²x = 16/9.