If (x + y)^2 – xy = 0, then find the value of (x^3 – y^3)/(x - y) ?

(x³ − y³)/(x − y) = x² + xy + y². Since (x + y)² − xy = x² + 2xy + y² − xy = x² + xy + y², and this is given to be 0, the value is 0.