RRB NTPC · Question 97
What is the minimum value of ‘Y’ for which 267Y2 is divisible by 3?
Show answer & explanation
Answer: (B) 1
Explanation
A number is divisible by 3 if its digit sum is. 2 + 6 + 7 + Y + 2 = 17 + Y; the smallest Y that makes this a multiple of 3 is 1 (17 + 1 = 18).