RRB NTPC · Question 41
Divide 3740 in three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. A. 700, 1000, 2040 B. 340, 1360, 2040 C. 680, 1020, 2040 D. 500, 1200, 2040
Show answer & explanation
Answer: (D) C
Explanation
Let half of the first, one-third of the second and one-sixth of the third each equal k. Then the parts are 2k, 3k and 6k, with total 11k = 3740, so k = 340. The parts are 680, 1020 and 2040.