RRB NTPC · Question 87
If R019 is divisible by 11, find the value of the smallest natural number R. A. 5 B. 6 C. 7 D. 8
Show answer & explanation
Answer: (D) D
Explanation
A number is divisible by 11 when the difference between the sums of alternate digits is 0 or a multiple of 11. In R019: (R + 1) − (0 + 9) = R − 8. This is 0 when R = 8, so the smallest such R is 8 (8019 = 11 × 729).