RRB NTPC · Question 22
The length of a diagonal in cm of a rectangle of length 9 cm and width 6 cm is: A. \(3\sqrt {13} \) B. \(\pm 3\sqrt {13} \) C. 3√5 D. ±3√5
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Answer: (A) A
Explanation
Diagonal = √(9² + 6²) = √(81 + 36) = √117 = 3√13 cm. A length cannot be negative, so ± options are wrong.