RRB NTPC · Question 66
If 19x^2 = 100^2– 90^2, then find the value of x. A. 10 B. 9 C. 11 D. 12
Show answer & explanation
Answer: (B) A
Explanation
100² − 90² = (100 − 90)(100 + 90) = 10 × 190 = 1900. So 19x² = 1900, x² = 100 and x = 10.
RRB NTPC · Question 66
Answer: (B) A
100² − 90² = (100 − 90)(100 + 90) = 10 × 190 = 1900. So 19x² = 1900, x² = 100 and x = 10.