RRB NTPC · Question 15
If A + B = 90° and cos B = 1/3; then the value of sin A is: A. 1/2 B. 1/4 C. 1/3 D. 2/3
Show answer & explanation
Answer: (A) C
Explanation
Since A + B = 90°, A = 90° − B, so sin A = sin(90° − B) = cos B = 1/3.
RRB NTPC · Question 15
Answer: (A) C
Since A + B = 90°, A = 90° − B, so sin A = sin(90° − B) = cos B = 1/3.