RRB NTPC · Question 81
If a - b = 5 and a^2 + b^2 = 31 then find the value of ab? A. 4 B. 5 C. 2 D. 3
Show answer & explanation
Answer: (D) D
Explanation
(a − b)² = a² + b² − 2ab gives 25 = 31 − 2ab, so 2ab = 6 and ab = 3.
RRB NTPC · Question 81
Answer: (D) D
(a − b)² = a² + b² − 2ab gives 25 = 31 − 2ab, so 2ab = 6 and ab = 3.