RRB NTPC · Question 57
If 40x^2 = 734^2 – 234^2, then find the value of x. A) 110 B) 121 C) 11 D) 144
Show answer & explanation
Answer: (D) A
Explanation
734² − 234² = (734 − 234)(734 + 234) = 500 × 968 = 4,84,000. So x² = 12,100 and x = 110.
RRB NTPC · Question 57
Answer: (D) A
734² − 234² = (734 − 234)(734 + 234) = 500 × 968 = 4,84,000. So x² = 12,100 and x = 110.