RRB NTPC · Question 30
If 4x + 5y = 14 and x – 5y = 16 then the value of x and y are A. 10 and –6/5 B. 6 and 2 C. 10 and 6/5 D. 6 and – 2
Show answer & explanation
Answer: (B) D
Explanation
Add the two equations to eliminate y: (4x + 5y) + (x − 5y) = 14 + 16, so 5x = 30 and x = 6. Substitute in x − 5y = 16: 6 − 5y = 16, so y = −2. The values are 6 and −2.