RRB NTPC · Question 60
If cos θ + sin θ = m, sec θ + cosec θ = n, what is m/n? A. 1 B. sin θ cos θ C. sec θ cosec θ D. cot θ tan θ
Show answer & explanation
Answer: (A) B
Explanation
n = secθ + cosecθ = 1/cosθ + 1/sinθ = (sinθ + cosθ)/(sinθ cosθ) = m/(sinθ cosθ). So m/n = sinθ cosθ.