RRB NTPC · Question 23
The value of (sin θ + cos θ)^2 =
Show answer & explanation
Answer: (C) 1 + 2cosθsinθ
Explanation
(sin θ + cos θ)² = sin²θ + 2 sin θ cos θ + cos²θ. Since sin²θ + cos²θ = 1, this equals 1 + 2 sin θ cos θ.
Railways PYQCBT 1 2016
RRB NTPC · Question 23
Answer: (C) 1 + 2cosθsinθ
(sin θ + cos θ)² = sin²θ + 2 sin θ cos θ + cos²θ. Since sin²θ + cos²θ = 1, this equals 1 + 2 sin θ cos θ.