RRB NTPC · Question 21
If (a + b + c) = 6 and a^2 + b^2 + c^2 = 14, then (ab + bc + ca) = ?
Show answer & explanation
Answer: (B) 11
Explanation
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca). So 36 = 14 + 2(ab + bc + ca), giving ab + bc + ca = 11.
RRB NTPC · Question 21
Answer: (B) 11
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca). So 36 = 14 + 2(ab + bc + ca), giving ab + bc + ca = 11.