RRB NTPC · Question 26
Find the least number required to be added to 3105 so that it is exactly divisible by 3, 4, 5 and 6.
Show answer & explanation
Answer: (A) 15
Explanation
LCM of 3, 4, 5 and 6 is 60. The next multiple of 60 after 3105 is 3120 (60 × 52), so 3120 − 3105 = 15 must be added.