RRB NTPC · Question 27
cos^2 90° + cosec^2 90° - cot^2 45° = ?
Show answer & explanation
Answer: (B) 0
Explanation
cos 90° = 0, cosec 90° = 1/sin 90° = 1 and cot 45° = 1. So cos²90° + cosec²90° − cot²45° = 0 + 1 − 1 = 0.
Railways PYQCBT 1 2016
RRB NTPC · Question 27
Answer: (B) 0
cos 90° = 0, cosec 90° = 1/sin 90° = 1 and cot 45° = 1. So cos²90° + cosec²90° − cot²45° = 0 + 1 − 1 = 0.