RRB NTPC · Question 62
If a + b = 10 and a^2 + b^2 = 68 find a^3 + b^3.
Show answer & explanation
Answer: (D) 520
Explanation
ab = (100 − 68)/2 = 16. a³ + b³ = (a + b)³ − 3ab(a + b) = 1000 − 480 = 520.
Railways PYQCBT 1 2020
RRB NTPC · Question 62
Answer: (D) 520
ab = (100 − 68)/2 = 16. a³ + b³ = (a + b)³ − 3ab(a + b) = 1000 − 480 = 520.