RRB NTPC · Question 68
The horizontal distance between two towers is 40√3 m. The angle of depression of the top of the first tower when seen from the top of the second tower is 30°. If the height of the second tower is 130 m, find the height of the first tower.
Show answer & explanation
Answer: (B) 90 m
Explanation
The height difference = 40√3 × tan 30° = 40√3 × 1/√3 = 40 m. The first tower is 130 − 40 = 90 m high.