RRB NTPC · Question 23
if \(\tan \theta = \frac{1}{{\sqrt 5 }},\;cose{c^2}\theta = \) ?
Show answer & explanation
Answer: (D) 6
Explanation
tan θ = 1/√5, so cot θ = √5 and cot²θ = 5. Using cosec²θ = 1 + cot²θ = 1 + 5 = 6.
RRB NTPC · Question 23
Answer: (D) 6
tan θ = 1/√5, so cot θ = √5 and cot²θ = 5. Using cosec²θ = 1 + cot²θ = 1 + 5 = 6.