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Railways PYQCBT 2 2017

RRB NTPC · Question 21

Find the least number which should be added to 1456 so that it is divisible by 6, 5 and 4 without leaving a remainder.

  1. 6

  2. 61

  3. 44

  4. 16

Show answer & explanation

Answer: (C) 44

Explanation

The number must be divisible by LCM(6, 5, 4) = 60. The next multiple of 60 after 1456 is 1500 (60 × 25), so 1500 − 1456 = 44 must be added.