Railways PYQCBT 1 2016

RRB NTPC · Question 19

If x^2 = 25^2 – 15^2, then find the value of x. A. 40 B. 50 C. 20 D. 25

  1. B

  2. A

  3. C

  4. D

Show answer & explanation

Answer: (C) C

Explanation

x² = 25² − 15² = (25 − 15)(25 + 15) = 10 × 40 = 400, so x = 20.