RRB NTPC · Question 45
If cos 2θ = sin θ and θ lies between 0 and 90°, then θ will be:
Show answer & explanation
Answer: (B) 30°
Explanation
cos 2θ = 1 − 2sin²θ = sin θ, so 2sin²θ + sin θ − 1 = 0 and sin θ = 1/2. With θ between 0° and 90°, θ = 30°.
RRB NTPC · Question 45
Answer: (B) 30°
cos 2θ = 1 − 2sin²θ = sin θ, so 2sin²θ + sin θ − 1 = 0 and sin θ = 1/2. With θ between 0° and 90°, θ = 30°.