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Railways PYQCBT 1 2020

RRB NTPC · Question 60

ABCD is a parallelogram. Side BC is produced to E such that BC = CE. Join AE which intersects side CD at P. The area of triangle ABE is:

  1. less than the area of parallelogram ABCD

  2. = to 1/2 of the area of parallelogram ABCD

  3. = to 1/3 of the area of parallelogram ABCD

  4. = to the area of parallelogram ABCD

Show answer & explanation

Answer: (D) = to the area of parallelogram ABCD

Explanation

Triangle ABE has base BE = 2BC and the same height as the parallelogram. Its area = ½ × 2BC × h = BC × h, equal to the area of parallelogram ABCD.