RRB NTPC · Question 28
The value of \(\frac{6}{5}\) of \(\left(\frac{1}{3}+\frac{2}{4}\right)-\frac{5}{6}\) of \(\left(\frac{3}{10}+\frac{12}{20}\right)-\frac{1}{6}\) is:
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Answer: (A) \(\frac{1}{12}\)
Explanation
6/5 of (1/3 + 1/2) = 6/5 × 5/6 = 1. 5/6 of (3/10 + 3/5) = 5/6 × 9/10 = 3/4. Value = 1 − 3/4 − 1/6 = 12/12 − 9/12 − 2/12 = 1/12.