RRB NTPC · Question 69
The value of 5 sin 14° sec 76° + 3 cot 15° cot 75° + 2 tan 45° is:
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Answer: (B) 10
Explanation
sec 76° = 1/cos 76° = 1/sin 14°, so the first term is 5. cot 75° = tan 15°, so cot 15° cot 75° = 1 and the second term is 3. 2 tan 45° = 2. Total = 10.