NextMockSearch exams, e.g. SSC CGL, UPPSC, Lekhpal
Railways PYQCBT 1 2020

RRB NTPC · Question 23

The value of 200 ÷ (5.23 + 4.77) × \((3/5-2/10)\) + (5 – 2) is:

  1. 8

  2. 19

  3. 18

  4. 11

Show answer & explanation

Answer: (D) 11

Explanation

5.23 + 4.77 = 10 and 3/5 − 2/10 = 2/5. So 200 ÷ 10 × 2/5 + 3 = 20 × 0.4 + 3 = 8 + 3 = 11.