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Railways PYQCBT 1 2020

RRB NTPC · Question 71

In the given figure, PO and OQ are the radius of the circumcircle of ∆APQ. If ∠PAQ = 38°, then ∠PQO will be

Figure

  1. 76°

  2. 52°

  3. 112°

  4. 104°

Show answer & explanation

Answer: (B) 52°

Explanation

The angle at the centre is twice the angle at the circumference: ∠POQ = 2 × 38° = 76°. OP = OQ (radii), so triangle POQ is isosceles and ∠PQO = (180° − 76°)/2 = 52°.