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Railways PYQCBT 1 2020

RRB NTPC · Question 22

If \(\sqrt{4624}=68\), then the value of: \(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)

  1. 7.548

  2. 7.854

  3. 7.458

  4. 7.648

Show answer & explanation

Answer: (A) 7.548

Explanation

√46.24 = 6.8, √0.4624 = 0.68 and √0.004624 = 0.068. Sum = 7.548.