RRB NTPC · Question 35
In a game Rajesh lost \(\frac{1}{3}\) of his money in the first round of the game, in the second round he losses \(\frac{3}{5}\) of his remaining money and in the third round he lost \(\frac{4}{7}\) of the rest. He is left with what part of original sum of monely?
Show answer & explanation
Answer: (C) \(\frac{4}{35}\)
Explanation
After round 1: 2/3 left. After round 2: 2/3 × 2/5 = 4/15. After round 3: 4/15 × 3/7 = 4/35 of the original.