RRB NTPC · Question 63
The base of an isosceles triangle in 8 cm and one of its equal sides is 5 cm. The height of the vertex opposite to the base from the base is:
Show answer & explanation
Answer: (A) 3 cm
Explanation
The height from the apex bisects the base: half-base = 4 cm, so height = √(5² − 4²) = 3 cm.