NextMockSearch exams, e.g. SSC CGL, UPPSC, Lekhpal
Railways PYQCBT 2 2017

RRB NTPC · Question 102

An electric bulb of 60 W is connected to a source of 240 V. The current drawn by the bulb will be:

  1. 4 A

  2. 2.5 A

  3. 0.25 A

  4. 0.4 A

Show answer & explanation

Answer: (C) 0.25 A

Explanation

P = VI, so I = P/V = 60/240 = 0.25 A.