RRB NTPC · Question 54
If Cot \(x = \frac{5}{12}\), then Sec x + Cosec x = ?
Show answer & explanation
Answer: (B) 221/60
Explanation
cot x = 5/12 gives a 5–12–13 triangle: sec x = 13/5 and cosec x = 13/12. Sum = 156/60 + 65/60 = 221/60.
RRB NTPC · Question 54
Answer: (B) 221/60
cot x = 5/12 gives a 5–12–13 triangle: sec x = 13/5 and cosec x = 13/12. Sum = 156/60 + 65/60 = 221/60.