RRB NTPC · Question 51
In a circle with a radius of 10 cm. XY and PQ are two parallel chords 12 cm and 16 cm in length, respectively. The two chords are situated on the opposite sides of the centre. The distance between the chords is:
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Answer: (A) 14 cm
Explanation
Distance of a chord from the centre = √(r² − (half-chord)²): for the 12 cm chord √(100 − 36) = 8 cm, for the 16 cm chord √(100 − 64) = 6 cm. On opposite sides of the centre, they are 8 + 6 = 14 cm apart.