RRB NTPC · Question 53
The LCM of two numbers is 156 and their HCF is 26. If the difference between the numbers is also 26, then the sum of the numbers is:
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Answer: (B) 130
Explanation
Let the numbers be 26a and 26b with a, b co-prime. LCM = 26ab = 156, so ab = 6, and 26(a − b) = 26 gives a − b = 1. So a = 3, b = 2: the numbers are 78 and 52, summing to 130.