RRB NTPC · Question 58
The value of cos 12° + cos 84° + cos 168° + cos 96° is:
Show answer & explanation
Answer: (C) 0
Explanation
cos 168° = −cos 12° and cos 96° = −cos 84°, so the four terms cancel in pairs: the sum is 0.
Railways PYQCBT 1 2020
RRB NTPC · Question 58
Answer: (C) 0
cos 168° = −cos 12° and cos 96° = −cos 84°, so the four terms cancel in pairs: the sum is 0.